The distances of two planets from the Sun are 10^13 m and 10^12 m respectively. Find the ratio of time periods of the two planets.
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Answer:
10× root of 10
Explanation:
According to Kepler's Third Law, the square of the period of the orbit of a planet about the Sun is proportional to the cube of the semi-major axis of the orbit.
T² is directly proportional to r³
Where T is the time period and r is the distance
This can be written as:
T1÷T2 = (r1÷r2)^3÷2
T1÷T2 = 10^13 ÷ 10^12
Therfore T1÷T2 = 10× root of 10
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