The distances traversed, during equal intervals of time, by a body falling from rest, stand to one another in
the same ratio as the odd numbers beginning with unity [namely, 1: 3: 5: 7…...].” Prove it
Answers
Answered by
1
Explanation:
ANSWER
The distance traversed in nth second by a freely falling body is given by:
s
n
=0+
2
8
(2n−1) (initial velocity =0)
⇒s=
2
8
(2n−1)
So s is directly proportional to (2n−1) where n=1,2,3....
So in consecutive seconds of 1s,2s,3s and so on
Distance will vary as: 1m,(2×2−1)m,(2×3−1)m and so on
So s varies as: 1m,3m,5m,.....(Proved).
Answered By
toppr
Similar questions