the distribution below shows the number of wickets taken by bowlers in one day cricket matches find the mean number of wickets by using step deviation method.
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Answer:
Here,
the class size varies , and the xi's are
large .
Let us still apply the step deviation method
with
a = 200 ,
h = 20
mean = 200 +[ ( -106 )/45 ]×20
= 200 - 47.11
= 152.89
The average number of wickets taken
by these 45 bowlers in one - day
cricket is 152.89
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