Math, asked by champ8083, 4 months ago

the divisibility rule of 6,032 by 2 and 3.​

Answers

Answered by ananya4513
13

Answer:

Since the number 4,608 is both divisible by 2 and 3 then it must also be divisible by 6. The answer is YES. A number is divisible by 9 if the sum of the digits is divisible by 9. Example 1: Is the number 1,764 divisible by 9?

Answered by liyana8bpal
0

Answer:

if a number has to be divisible by 2 then visible by its last digit has to end with an even number.

If it has to be divisible by 3 then all it's digits have to sum up to a number divisible by three.

Step-by-step explanation:

1. divisibility of 6032 by 2

the number 6032 ends in 2

which is an even number.

so it is divisible by 2

2. divisibility of 6032 by 3

the digits of the number 6032 is

6  0  3  and  2

let us check their sum,

  6 + 0 + 3 + 2

= 6 + 3 + 2(because 6+0 = 6)

= 9 + 2(because 6+3 = 9)

= 11 (because 9+2 = 11)

so, the sum of digits of the number 6032 is 11 ( as shown above)

but the question is - is 11 divisible by 3

let us check:

3 multiplied by 1 = 3

3 multiplied by 2 = 6

3 multiplied by 3 = 9

3 multiplied by 4 = 12

when you check the three tables, you will see that:

after 9, which is lesser than 11,

comes 12, which is greater than 11,

this shows that there is no place for 11 in three tables.

so 6032 is not divisible by 3.

answer: 6032 is divisible by 2

whereas, not divisible by 3.

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