The divisor quotient and remainder of a polynomial are 9x+1, 9x-1 and 8 respectively . Then the polynomial is
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divisor=dividend*quotient + remainder
p(x)=(9x+1)(9x-1)+8
by the identity (a+b)(a-b)=a^2-b^2
p(x) = 81x^2-1+8
p(x)=81x^2-7
the polynomial is 81x^2-7
p(x)=(9x+1)(9x-1)+8
by the identity (a+b)(a-b)=a^2-b^2
p(x) = 81x^2-1+8
p(x)=81x^2-7
the polynomial is 81x^2-7
Answered by
2
Answer:
81x square+7
Step-by-step explanation:
9x+1,9x-1 -8
9x*9x-1*1-8
81x square -1-8
81x square 7
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