Question

The divisor quotient and remainder of a polynomial are 9x+1, 9x-1 and 8 respectively . Then the polynomial is

Answer 1

divisor=dividend*quotient + remainder
p(x)=(9x+1)(9x-1)+8
by the identity (a+b)(a-b)=a^2-b^2
p(x) = 81x^2-1+8
p(x)=81x^2-7
the polynomial is 81x^2-7

Answer 2

Answer:

81x square+7

Step-by-step explanation:

9x+1,9x-1 -8

9x*9x-1*1-8

81x square -1-8

81x square 7