Question

The domain
of 1x²4j is?
M-2​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:

We have f(x)=1[x]2−7[x]−8

Clearly f(x) is not defined if [x]2−7[x]−8=0

⇒([x]−8)([x]+1)=0

⇒[x]=−1 or 8

⇒x∈[−1,0] or x∈[8,9)

So, domain of f(x) is (−∞,−1)∪[0,8)∪[9,∞)

Step-by-step explanation: