Question

the domain of f(x) = √2-2^x-2^2^x is


no irrelevant ans​

Answer 1

Step-by-step explanation:

Let y=2^x

r(x)=R(y)=2-y-y²=-(y²+y-2)=-(y+2)(y-1)

For R(y) ≥0→(y+2)(y-1)≤ 0

-2≤ y≤1→

Since y=2^x is >0

we take 0<y≤1

0<2^x≤1→

→x≤0

∴Df=(-∞,0]