Question

.The domain of f(x) = log₂ (x² - 6x +10) is
please answer this i will mark the answerer brainliest​

Answer 1

SOLUTION

TO DETERMINE

The domain of the function

$\sf{f(x) = log_{2}( {x}^{2} - 6x + 10) }$

EVALUATION

Here the given function is

$\sf{f(x) = log_{2}( {x}^{2} - 6x + 10) }$

The function is well defined when

$\sf{( {x}^{2} - 6x + 10) > 0 }$

$\sf{ \implies \: ( {x}^{2} - 6x + 9 + 1) > 0 }$

$\sf{ \implies \: {(x - 3)}^{2} + 1> 0 }$

Which is valid for all real values of x

Hence the domain = Set of all real numbers

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Answer 2

Step-by-step explanation:

SOLUTION

TO DETERMINE

The domain of the function

\sf{f(x) = log_{2}( {x}^{2} - 6x + 10) }f(x)=log2(x2−6x+10)

EVALUATION

Here the given function is

\sf{f(x) = log_{2}( {x}^{2} - 6x + 10) }f(x)=log2(x2−6x+10)

The function is well defined when

\sf{( {x}^{2} - 6x + 10) > 0 }(x2−6x+10)>0

\sf{ \implies \: ( {x}^{2} - 6x + 9 + 1) > 0 }⟹(x2−6x+9+1)>0

\sf{ \implies \: {(x - 3)}^{2} + 1 > 0 }⟹(x−3)2+1>0

Which is valid for all real values of x

Hence the domain = Set of all real numbers

━━━━━━━━━━━━━━━━

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1. Using brackets, write 2 pairs of numbers whose sum is 12. Write one equality using

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