the domain of function f(x) = x^2 + 1 / log(x^2 + 1 )
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ln (x²+1) ≠0 as it is in denominator
x²+1 ≠1
x²≠0
X ≠0
and x²+1 should be greater than 0 since it is number of a log
x² always +ve
thus x²+1 > 0 always
so domain will be X € R-{0}
x²+1 ≠1
x²≠0
X ≠0
and x²+1 should be greater than 0 since it is number of a log
x² always +ve
thus x²+1 > 0 always
so domain will be X € R-{0}
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Answer:
what is the domaine of f(x)=1-(logx)²
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