Question

the domain of function f(x) = x^2 + 1 / log(x^2 + 1 )

Answer 1

ln (x²+1) ≠0 as it is in denominator
x²+1 ≠1
x²≠0
X ≠0
and x²+1 should be greater than 0 since it is number of a log
x² always +ve
thus x²+1 > 0 always
so domain will be X € R-{0}

Answer 2

Answer:

what is the domaine of f(x)=1-(logx)²

Step-by-step explanation: