The domain of sin inverse of log x÷3
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Domain of sin-1x is [-1,1]
Therefore, -1 ≤ log3(x/3) ≤ 1
3-1 ≤ x/3 ≤ 3
1 ≤ x ≤ 9
Therefore, the domain of sin-1[log3(x/3)] is [1,9]
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