Math, asked by choudhuryronit92, 6 hours ago

The domain of tan^-1 (2x + 1) is
(with calculation)

Answers

Answered by pulakmath007
2

SOLUTION

TO DETERMINE

The domain of the function

 \sf{ { \tan}^{ - 1}(2x + 1) }

EVALUATION

Here the given function is  \sf{ { \tan}^{ - 1}(2x + 1) }

We know that  \sf{ { \tan}^{ - 1}x } is well defined when

  \sf{ -  \infty  < x <  +   \infty }

Thus we can say that  \sf{ { \tan}^{ - 1}(2x + 1) } is well defined when

 \sf{ -  \infty  < 2x + 1 < +   \infty }

 \sf{ \implies \:  -  \infty  < x  < +   \infty }

Hence the required Domain is

 \sf{ (-  \infty \:   , \: +   \infty )}

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