Question

the domain of
$f(x) = \sqrt{} 2 - log_{3}(x - 1)$
​

Answer 1

Step-by-step explanation:

for logarithm to be defined x-2>0

⇒x>2

for the square root to be defined 2-$log_{3}$(x-1) $\geq$0

9$\geq$x-1

x$\leq$10

so the domain of the function is (2,10]