Math, asked by jayagedar9416, 1 day ago

The domain of the function 5cos-1 2x/3 is

Answers

Answered by senboni123456
0

Answer:

Step-by-step explanation:

We have,

\tt{f(x)=5\,cos^{-1}\left(\dfrac{2x}{3}\right)}

Now, f(x) is defined, if and only if

\sf{-1\le\dfrac{2x}{3}\le1}

\sf{\implies-3\le2x\le3}

\sf{\implies-\dfrac{3}{2}\le\,x\le\dfrac{3}{2}}

\sf{Hence,\,\,\,dom(f)\in\left[-\dfrac{3}{2},\dfrac{3}{2}\right]}

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