Question

The domain of the function f(x)=1/(x^ 2 -3x+2)is​

Answer 1

Answer:

Step-by-step explanation:

The function is not defined when  

1 − x ^2  =0

1 = x^2

x = √ 1

x = ± 1

So the domain of function is R−{±1}

Let

1 / 1 - x^2 = y

1 = y − yx^ 2

yx^ 2  =y − 1

x^2  = y - 1 / y

x = √ y - 1  / y

So the Range is R − [0,1]

Answer 2

Step-by-step explanation:

f(x) = 1/(x^2 - 3x + 2)

x^2 - 3x + 2 ≠ 0

(x-2)(x-1) ≠ 0

x ≠ 1 and x ≠ 2

Therefore, the domain : {x ∈ ℝ : x ≠ 1 and x ≠ 2}