Question

The domain of the function f(x) ݂ x2+2x+1 ÷ x2-x-6 a)R-{3,-2} b) R-{-3,2} c)R-[3,-2] d) R-(3,-2) ​

Answer 1

$\large\rm { f(x) = \frac{x^{2} +2x+1}{x^{2} - x -6} }$

f(x) is defined if,

$\large\rm { \implies (x-3)(x+2) = 0}$

so, option b is correct.

Answer 2

Answer:

f(x)=

f(x)= x

f(x)= x 2

f(x)= x 2 −x−6

f(x)= x 2 −x−6x

f(x)= x 2 −x−6x 2

f(x)= x 2 −x−6x 2 +2x+1

f(x)= x 2 −x−6x 2 +2x+1

f(x)= x 2 −x−6x 2 +2x+1

f(x)= x 2 −x−6x 2 +2x+1 f(x) is defined if,

f(x)= x 2 −x−6x 2 +2x+1 f(x) is defined if,(x-3)(x+2) = 0}⟹(x−3)(x+2)=0

f(x)= x 2 −x−6x 2 +2x+1 f(x) is defined if,(x-3)(x+2) = 0}⟹(x−3)(x+2)=0so, option b is correct.