Question

The domain of the function y=f(x)=1/root x-1 is

Answer 1

Answer:

Domain : x ∈ $\mathbb{R}$ , x > 1

Range : x ∈ $\mathbb{R}$

Step-by-step explanation:

$y = f(x) = \dfrac{1}{\sqrt{x - 1}}$

We have to find domain of f(x) i.e. acceptable acceptable inputs/values of x. Inorder to have real range of y, ${\sqrt{x - 1}}$ should be a positive number or in other words we can say it should be greater than zero.

$So,\; x - 1>0$

$\implies x > 0 + 1$

$\implies x > 1$

∴ Domain : x ∈ $\mathbb{R}$ , x > 1

∴ Range : x ∈ $\mathbb{R}$