Question

The dome of the temple is 5 cm thick.the inner radius is 0.14 m.
1.Find the outer surface area.
2.And cost of whitewashing the outer surface at the rate of 100 rupees per 5 cm square. ​

Answer 1

Step-by-step explanation:

inner radius=0.14m=14cm

outer radius =14+5=19cm

curved surface area of dome(hemisphere)=2×pi×r^2

=2×3.14×(19)^2

=6.28×361

=2267.08cm^2

cost of whitewashing=100×2267.08/5

=50×2267.08

=1,13,350₹

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