Question

The donations given to an orphanage home by the students of different classes of a secondary
school are given below.
No. of students donated
Donation by each student (in :)
5
15
15
7
20
10
DX
15
16
Х
20
14
Find the mean, median and mode of the data.​

Answer 1

Answer:

Donation by each student No. of students donated

Cumulative frequency

5 15 15

7 15 30

10 20 50

15 16 66

20 14 80

To find the mean we will add up total cost of packets , then divide by total number of packets.

So,

Mean =

(5×15+7×15+10×20+15×16+20×14)/(15+15+20+16+14)

Mean =(75+105+200+240+280)/80=900/80=11.26

As we can see that the donation of greatest number of student is Rs. 10 each, so the mode will be 10

As we can see there are 80 students arranged in increasing order of their respective donations. So, the middle one will be (80)/2=40

th

and 41

st

student in the list.

So, the median will be the donation by student corresponding to cumulative frequency just greater or equal to 40 and 41 , i.e., 10

Therefore , median is 10