Question

The drain cleaner drainer contains small bits of aluminium which reacts with caustic soda to form H2 .
Volume of hydrogen released at 20°C and 1bar when 0.15 gm of aluminium reacts caustic soda is ?

Answer 1

Answer:

Answers

Me · Beginner

Know the answer? Add it here!

abhi178

abhi178 Genius

Al react with caustic soda to produce dihydrogen. reaction will be

2Al + 2NaOH + 2H2O -->2NaAlO2 + 3H2

here we see that, 2 mol of Al produce 3 mole of H2

∴ 2 × 27 g of Al produce 3 × 2 g of H2 .

∴ 54 g of Al produce 6g of H2.

∴ 1 g of Al produce 6/54 = 1/9 g of H2.

∴ 0.15g of Al produce 0.15/9 g of H2

so, number of mole of H2 produce = weight of HE produce/molar weight of H2

= (0.15/9)/2

= 0.15/18 = 0.00833 mol

now, use formula, PV = nRT

Here, P = 1 bar or 0.987 atm

T = 20°C or 293K

n = 0.00833 mol

R = 0.0821 atm dm³/K/mol

V = ?

V = 0.00833 × 0.0821 × 293/0.987

= 0.203 dm³

we know, 1 dm³ = 1000 mL

so, Volume of H2 = 1000× 0.203mL = 203mL

Plz mark brainliest