The driver of a 2.0 × 103 kg red car traveling on the highway at 45m/s slams on his brakes to avoid striking a second yellow car in front of him, which had come to rest because of blocking ahead as shown in above Fig. After the brakes are applied, a constant friction force of 7.5 × 103 N acts on the car. Ignore air resistance.
(a) Determine the least distance should the brakes be applied to avoid a collision with the other vehicle?
(b) If the distance between the vehicles is initially only 40.0 m, at what speed would the collision occur?
(c) Write your conclusive observations on the result obtained from this numerical. i.e. the importance of Physics in daily life.
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Answer:
Question No. 4 Contract price Rs.10,00,000, Cost incurred to date Rs.4,00,000, Work certified Rs.5,60,000, Cash received 80% of work certified, Work uncertified Rs.2,60,000. Profit to be credited to profit & loss account
Koi h?Question No. 4 Contract price Rs.10,00,000, Cost incurred to date Rs.4,00,000, Work certified Rs.5,60,000, Cash received 80% of work certified, Work uncertified Rs.2,60,000. Profit to be credited to profit & loss account
Koi h?Question No. 4 Contract price Rs.10,00,000, Cost incurred to date Rs.4,00,000, Work certified Rs.5,60,000, Cash received 80% of work certified, Work uncertified Rs.2,60,000. Profit to be credited to profit & loss account
Koi h?
Explanation:
ku kya huo thu ko??
Answer:
An acid – base titration is used to determine the unknown concentration of an acid or base by neutralizing it with an acid or base of known concentration.
Neutralization is the reaction between an acid and a base, producing a salt and a neutralized base.
A strong acid yields a weak conjugate base (A–), so a strong acid is also described as an acid whose conjugate base is a much weaker base than water.