The driver of a car driving at the speed of 38 km/hr locates a bus 40
meters ahead of him. After 20 seconds, the bus is 60 meters behind. Find the
speed of the bus.
Answers
The driver of a car driving at the speed of 38 km/h located a bus 40 m ahead of him. after 20 seconds, the bus is 60 m behind.
We have to find the speed of the bus.
solution : speed of car = 38 km/h = 38 × 5/18 = 10.55 m/s
initial bus is 40 ahead of a car but after 20 seconds it is 60 behind of the car.
so distance gained by car over the bus in 20 seconds = 40 + 60 m = 100m
using formula,
Time = relative distance/relative speed
⇒20 seconds = 100m/( 10.55 - v) , let the speed of bus is v
⇒20 = 100/(10.55 - v)
⇒v = 10.55 - 5 = 5.55 m/s = 5.55 × 18/5 km/h
= 20 km/h
Therefore the speed of the bus is 20 km/h.
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Answer:
The driver of a car driving at the speed of 38 km/h located a bus 40 m ahead of him. after 20 seconds, the bus is 60 m behind.
We have to find the speed of the bus.
solution : speed of car = 38 km/h = 38 × 5/18 = 10.55 m/s
initial bus is 40 ahead of a car but after 20 seconds it is 60 behind of the car.
so distance gained by car over the bus in 20 seconds = 40 + 60 m = 100m
using formula,
Time = relative distance/relative speed
⇒20 seconds = 100m/( 10.55 - v) , let the speed of bus is v
⇒20 = 100/(10.55 - v)
⇒v = 10.55 - 5 = 5.55 m/s = 5.55 × 18/5 km/h
= 20 km/h
Therefore the speed of the bus is 20 km/h.
Step-by-step explanation: