Question

The driver of a car travelling with a speed v suddenly applies brake. The speed is halved by the time the car travels a distance of 12m.How much further will the car travel before it comes to rest?

Answer 1

Answer:

$4m$

Explanation:

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Answer 2

Given:

For 1st case:

Initial velocity = v

Final velocity = v/2

Distance = 12 m

For 2nd case:

Initial velocity = v/2

Final velocity = 0

To Find:

The distance further covered by the car before it comes to rest.

Calculation:

- Applying third equation of motion to the first case we get:

v² = u² + 2as

(v/2)² = v² + 2 × a × 12

⇒ v²/4 - v² = 24 a

⇒ -3 v²/4 = 24 a

⇒ a = - v²/32

- Applying third equation motion to the second case, we get:

v² = u² + 2as

0² = (v/2)² + 2 × (- v²/32) × s

⇒ v² × s / 16 = v² / 4

⇒ s = 4 m

- So, the car will further travel 4 m before it comes to rest.