Question

The driver of a three wheeler moving with a speed of 36 km/h sees a child standing in the middle of the road and brings his vehicle to rest in 4.0 s just in time to save the child. What is the average retarding force on the vehicle? The mass of the three wheeler is 400 kg and the mass of the driver is 65 kg.

Answer 1

Hey mate,

# Answer-
1162.5 N in opposite direction.

## Explaination-
# Given-
u = 36 km/h = 10 m/s
v = 0
t = 4 s
mv = 400 kg
md = 65 kg

# Solution-
Total mass of vehicle and driver,
M = mv + md = 400 + 65 = 465 kg.

Now retarding force is given by,
F = Ma
F = M(v-u)/t
F = 465(0-10)/4
F = -1162.5 N

Force will be 1162.5 N in opposite direction.

Hope I was helpful...

Answer 2

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$\bold\red{hello...frd\:swigy\:here}$

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u = 36 km/h

v = 10 m/s

t = 4 s

Mass of three- wheeler, m = 400 kg

Mass of the driver, m' = 65 kg

Total mass of the system, M = 400 + 65 = 465 kg

▪Using the first law of motion, the acceleration (a) of the three-wheeler can be calculated as:

v = u + at

=> a= v- u / t = (0-36)/4 = -9 m/s^2

◾The negative sign indicates that the velocity of the three-wheeler is decreasing with time.

◾Using Newton’s second law of motion, the net force acting on the three-wheeler can be calculated as:

F = Ma = 465 × (–9) = –1162.5 N

◾The negative sign indicates that the force is acting against the direction of motion of the three-wheeler.

I hope, this will help you___❤❤

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