Question

The driver of a three-wheeler moving with a speed of 36km/h sees a child standing in the middle of the road and brings his vehicle to rest in 4.0s

Answer 1

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u = 36 km/h

v = 0 m/s

t = 4 s

▪Using the first law of motion, the acceleration (a) of the three-wheeler can be calculated as:

v = u + at

=> a= v- u / t = (0-36)/4 = -9 m/s^2

◾The negative sign indicates that the velocity of the three-wheeler is decreasing with time.

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Answer 2

Explanation:

Initial speed of the three-wheeler, u = 36 km/h = 10 m/s

Final speed of the three-wheeler, v = 0 m/s

Time, t = 4 s

Mass of the three-wheeler, m = 400 kg

Mass of the driver, m' = 65 kg

Total mass of the system, M = 400 + 65 = 465 kg

Using the first law of motion, the acceleration (a) of the three-wheeler can be calculated as:

v = u + at

∴ a = (v - u) / t = (0 - 10) / 4 = -2.5 ms-2

The negative sign indicates that the velocity of the three-wheeler is decreasing with time.

Using Newton’s second law of motion, the net force acting on the three-wheeler can be calculated as:

F = Ma

= 465 × (–2.5) = –1162.5 N

The negative sign indicates that the force is acting against the direction of motion of the three-wheeler.