The driver of a three wheeler moving with
a velocity of 40 kmh 1 sees a child
Standing in the middle of the road and brings
his vehicle to rest in 5 seconds
time to save the child - What is the
average retarding force on the vehicle. The
mass of the three wheeler is 500kg and
the mass of the driver is 70kg
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Answer:
ANSWER
Given:
Initial speed of the three-wheeler, u=36km/h=10m/s
Final speed of the three-wheeler, v=0 m/s
Time, t=4s
Mass of the three-wheeler, m=400 kg
Mass of the driver, m
′
=65kg
Total mass of the system, M=400+65=465 kg
Using the first law of motion, the acceleration (a) of the three-wheeler can be calculated as:
v=u+at
a=
t
(v−u)
=
4
(0−10)
=−2.5m/s
2
The negative sign indicates that the velocity of the three-wheeler is decreasing with time.
Using Newton's second law of motion, the net force acting on the three-wheeler can be calculated as:
F=Ma=465×(−2.5)=−1162.5N
The negative sign indicates that the force is acting against the direction of motion of the three-wheeler.
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