Question

The driver of a train a running and 25 m per second sights a train be moving in the same direction on the same track with 15 M per second the driver of train a applies break to produce a deceleration of 1 M per second square what should be the minimum distance between a trains to avoid accident

Answer 1

We can solve this question using relative motion

Let the train A move at 25m/s and train B at 15m/s

Then the relative velocity of train A wrt B will be 25-15=10m/s

Using $v^{2}=u^{2}+2as$

and by apply the initial velocity u as 10 and final velocity v as 0 and a as -1

Thus by substituting the valuse we get the distance s as 50 m