Question

The driver of a train traveling at 40m/s applies the brake, as the train enter a station
The train slows down at a rate of 2m/s. The platform is 400m long,
Will the train stop in time?numerical
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Answer 1

Answer:

yes

Explanation:

because from third equation of motion we can get the value of final velocity that will be zero.

so train will stop in time

Answer 2

Answer:

Initial velocity(u) of the train= 40m/s  

Final velocity(v) of the train= 0m/s

Retardation(a) = -2m/s2

 Distance(s) = (v2-u2)/2a  = (0- 402) / (2x -2)

   =( -1600)/ ( -4 )

  =   400m

Hence the train will stop after covering a distance of 400m.

Explanation: