The driver of the train travelling at 40m/s applies the brakes as the train enters a station. The train slows down at a rate of 2m/s^2.The platform is 400 m long.Will the train stop in time?
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Answer:
YES
Explanation:
Given parameters:
Initial velocity(u) of the train= 40m/s
Final velocity(v) of the train= 0m/s
Retardation(a) = -2m/s2
Distance(s) = (v2-u2)/2a = (0- 402) / (2x -2)
=( -1600)/ ( -4 )
= 400m
Hence the train will stop after covering a distance of 400m.
Since the length of the platform is also 400m, it can be concluded that:
Yes, the train will stop in time.
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