Math, asked by creativeabhinoor, 7 months ago

The driver of train A travelling at a speed of 54 km/h, he applies brakes and retards the train uniformly. The train stops in 5 seconds. Another train B is travelling on the parallel with a speed of 36 km/h. Its driver applies the brakes and the train retards uniformly and hence stops in 10 seconds. Which of the trains travelled farther after the brakes were applied? Please explain with steps, thanks

Answers

Answered by parisbabu79
11

Answer:

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Answered by amitnrw
3

Given : The driver of train A travelling at a speed of 54 km/h  applies brakes and retards the train uniformly. The train stops in 5 seconds.

Another train B is travelling on the parallel with a speed of 36 km/h  ,  Its driver applies the brakes and the train  retards uniformly; train B stops in 10 seconds.

To Find : Plot speed-time graphs for both  the trains on the same axis.

Which of the trains travelled farther after the brakes  were applied?​

Solution:

Train A  = 54 km/h  =  54 * 5 / 18  = 15 m/s

Time = 5 sec

Distance covered  =  5 *( 15 + 0)/2  = 37.5 m

acceleration = ( 0 - 15)/5 = - 3 m/s²

Time    Speed

0            15

1              12

2            9

3            6

4           3

5            0

Train B  = 36 km/h  =  36 * 5 / 18  = 10 m/s

Time = 10  sec

Distance covered  =  10 *( 10 + 0)/2  = 50 m

a = ( 0 - 10)/10  = - 1 m/s²

Time    Speed

0            10

1              9

2            8

3            7

4            6

5            5

6           4

7           3

8           2

9           1

10          0

 trains B travelled farther after the brakes  were applied

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