The driver of train A travelling at a speed of 54 km/h, he applies brakes and retards the train uniformly. The train stops in 5 seconds. Another train B is travelling on the parallel with a speed of 36 km/h. Its driver applies the brakes and the train retards uniformly and hence stops in 10 seconds. Which of the trains travelled farther after the brakes were applied? Please explain with steps, thanks
Answers
Answer:
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Given : The driver of train A travelling at a speed of 54 km/h applies brakes and retards the train uniformly. The train stops in 5 seconds.
Another train B is travelling on the parallel with a speed of 36 km/h , Its driver applies the brakes and the train retards uniformly; train B stops in 10 seconds.
To Find : Plot speed-time graphs for both the trains on the same axis.
Which of the trains travelled farther after the brakes were applied?
Solution:
Train A = 54 km/h = 54 * 5 / 18 = 15 m/s
Time = 5 sec
Distance covered = 5 *( 15 + 0)/2 = 37.5 m
acceleration = ( 0 - 15)/5 = - 3 m/s²
Time Speed
0 15
1 12
2 9
3 6
4 3
5 0
Train B = 36 km/h = 36 * 5 / 18 = 10 m/s
Time = 10 sec
Distance covered = 10 *( 10 + 0)/2 = 50 m
a = ( 0 - 10)/10 = - 1 m/s²
Time Speed
0 10
1 9
2 8
3 7
4 6
5 5
6 4
7 3
8 2
9 1
10 0
trains B travelled farther after the brakes were applied
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