Question

the dry density of a soil is 1.5 g/cm3. if the saturation water content is 50%, then its saturated density and submerged density will respectively be

Answer 1

Given:

Dry density = 1.5 g / cu.cm

Water content = 50%

To find:

The saturated density and submerged density.

Solution:

To find the saturation density,

Saturation density = rd ( 1 + w )

Where,

rd = r ω g / 1 + e

w = Weight

Substituting the values,

Saturation density = 1.5 * 1.5

Saturation density = 2.25 g / cc

To find the submerged density,

Submerged density = Saturated density - rw

Substituting the values,

Submerged density =  2.25 - 1

Submerged density = 1.25 gm / cc

Answer 2

Explanation:

Given:

Dry density = 1.5 g / cu.cm

Water content = 50%

To find:

The saturated density and submerged density.

Solution:

To find the saturation density,

Saturation density = rd ( 1 + w )

Where,

rd = r ω g / 1 + e

w = Weight

Substituting the values,

Saturation density = 1.5 * 1.5

Saturation density = 2.25 g / cc

To find the submerged density,

Submerged density = Saturated density - rw

Substituting the values,

Submerged density = 2.25 - 1

Submerged density = 1.25 gm / cc