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The E^0M^2+,/M for copper is positive (0.34 V). Copper is the only metal in the first series of transition

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Answered by shaurya925
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The E0 (M2+/M) for copper is + ve. This is because high energy is required to transform Cu to Cu2+ which is not balanced by its hydration enthalpy. The E^0M^2+,/M for copper is positive (0.34 V). Copper is the only metal in the first series of transition
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