Question

The e.m.f. of a cell is 1.09v and its internal resistance is 2ohm if the terminal of the cell are joined by a wire of resistance 18ohm find the potential difference recorded by a high resistance voltmeter connected to the terminal of a cell

Answer 1

r is the internal resistance.

R is the external resistance.

ε is the emf of the cell.

Using Kirchoff's voltage law, −2+I(r+R)=0

I=

4

2

=0.5A

Potential difference across the cell,V=ε−Ir=2−0.05=1.95V

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