Question

The e.m.f. of a Daniell cell at 298 K is E₁.fig.1.When the concentration of ZnSO₄ is 1.0 M and that of CuSO₄ is 0.01 M, the e.m.f. changed to E₂. What is the relationship between E₁ and E₂?
(a) $E_2 = 0 \neq E_1$
(b) E₁ > E₂
(c) E₁ < E₂
(d) E₁ = E₂

Answer 1

$<b>$
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The e.m.f. of a Daniell cell at 298 K is E₁.fig.1.When the concentration of ZnSO₄ is 1.0 M and that of CuSO₄ is 0.01 M, the e.m.f. changed to E₂. What is the relationship between E₁ and E₂?
(a) $E_2 = 0 \neq E_1$
(b) E₁ > E₂
(c) E₁ < E₂
(d) E₁ = E₂

→ [B]


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Answer 2

Answer :

_________________________

The e.m.f. of a Daniell cell at 298 K is E₁.fig.1.When the concentration of ZnSO₄ is 1.0 M and that of CuSO₄ is 0.01 M, the e.m.f. changed to E₂. What is the relationship between E₁ and E₂?

(a) E_2 = 0 \neq E_1

(b) E₁ > E₂

(c) E₁ < E₂

(d) E₁ = E₂

_______________________________-

The correct option is (b) :  E₁ > E₂

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hope it helps :)

thanks :)