Physics, asked by anjana5124, 3 months ago

The ear A of mass 1500 kg, travelling at 25 m/s collides with another car B of
mass 1000 kg travelling af 15 m/s in the same direction. After collision the
velocity of car A becomes 20 m/s.
(1) What is the momentum of the car A before collision?
(a) 30000 km/s
(b) 37500 kg m/s
( 15000 kgm/s
(d) 52500 kg. m/s
What is the total momentum of car A and car B before collision?
(03750 kg. m/s
(b) 37500 kg. m/s
(c) 15000 kg, m/s
(d) 52500 kg. m/s

please answer this question​

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Answers

Answered by dipamcool2016
17

Answer:

Given,

Mass 1 (m₁) = 1500 kg

Initial Velocity 1 (u₁) = 25 m/s

Mass 2 (m₂) = 1000 kg

Initial Velocity (u₂) = 15 m/s

Final Velocity 1 (v₁) = 20 m/s

i. Momentum of Car A before collision = m₁u₁

= (1500*25) kg.m/s

= 37500 kg.m/s

ii. Momentum of Car B before collision = m₂u₂

= (1000*15) kg.m/s

= 15000 kg.m/s

Total Momentum of Car A and B before Collision = m₁u₁+m₂u₂

= (37500+15000) kg.m/s

= 52500 kg.m/s

iii. Let the Velocity of Car B after Collision be v₂.

According to law of conservation of momentum,

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

= 52500 = (1500*20) + (1000v₂)

= 52500 = 30000 + 1000v₂

= 22500 = 1000v₂

= 22.5 m/s = v₂

i. The Momentum of Car A before Collision is 37500 kg.m/s

ii. The Total Momentum of Car A and B before Collision is 52500 kg.m/s

iii. The Velocity of Car B after Collision will be 22.5 m/s

I hope this helps.

Answered by anjumanyasmin
1

From the given question the correct answer is;

i. The Momentum of Car A before Collision is 37500 kg.m/s

ii. The Total Momentum of Car A and B before Collision is 52500 kg.m/s

iii. The Velocity of Car B after Collision will be 22.5 m/s

Solution:

Given,

Mass 1 (m₁) = 1500 kg

Initial Velocity 1 (u₁) = 25 m/s

Mass 2 (m₂) = 1000 kg

Initial Velocity (u₂) = 15 m/s

Final Velocity 1 (v₁) = 20 m/s

i. Momentum of Car A before collision = m₁u₁

= (1500*25) kg.m/s

= 37500 kg.m/s

ii. Momentum of Car B before collision = m₂u₂

= (1000*15) kg.m/s

= 15000 kg.m/s

Total Momentum of Car A and B before Collision = m₁u₁+m₂u₂

= (37500+15000) kg.m/s

= 52500 kg.m/s

iii. Let the Velocity of Car B after Collision be v₂.

According to law of conservation of momentum,

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

= 52500 = (1500*20) + (1000v₂)

= 52500 = 30000 + 1000v₂

= 22500 = 1000v₂

= 22.5 m/s = v₂

i. The Momentum of Car A before Collision is 37500 kg.m/s

ii. The Total Momentum of Car A and B before Collision is 52500 kg.m/s

iii. The Velocity of Car B after Collision will be 22.5 m/s

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