Math, asked by toxicnucleo, 13 days ago

The earth is assumed to be a sphere of radius (R) rotating about its axis with an angular speed . If the effective acceleration due to gravity at a certain latitude () is 2 p 3 g R 4   , where gp is the acceleration due to gravity at the poles, then the value of  is​

Answers

Answered by ruchikhanakmitpaoh4p
2

Answer:

Acceleration due to gravity at a place of latitude λ due to rotation of earth is g  

=g−R  

E

ω  

2

cos  

2

λ

At equator, λ=0,cos0=1

∴g  

=g  

e

=g−R  

E

ω  

2

 

At poles, λ=90,cos90=0

∴g  

=g  

p

=g

∴g  

p

−g  

e

=g−(g−R  

E

ω  

2

)=R  

E

ω  

2

Step-by-step explanation:

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