The earth is assumed to be a sphere of radius (R) rotating about its axis with an angular speed . If the effective acceleration due to gravity at a certain latitude () is 2 p 3 g R 4 , where gp is the acceleration due to gravity at the poles, then the value of is
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Answer:
Acceleration due to gravity at a place of latitude λ due to rotation of earth is g
′
=g−R
E
ω
2
cos
2
λ
At equator, λ=0,cos0=1
∴g
′
=g
e
=g−R
E
ω
2
At poles, λ=90,cos90=0
∴g
′
=g
p
=g
∴g
p
−g
e
=g−(g−R
E
ω
2
)=R
E
ω
2
Step-by-step explanation:
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