Question

The earth moves round the sun in a near circular orbit of radius
$1.8 \times 10^{ 11} m$
Its centripetal acceleration is:​

Answer 1

Answer:

Explanation:

Consider that in one year the Earth travels the entire circumference of the circle (ok, it should be an ellipse but let us assume it is a circle) of radius  

r = 1.8 × 10 ^11m

So: in  1  year,  363  days, each day  24  hours, each hour  60  minutes and each

minute  60  seconds, or:

365 × 24 × 60 × 60

= 3.15 × 10  ^7 m

≈ 3 × 10  ^7  seconds.

Describing a distance of  2 π r = 2 x 3.14 x 1.8× 10  ^11

= 11.304 × 10  ^11 m

≈ 11× 10  ^11 m

Velocity will be:  v = distance /time

=

11× 10  ^11  / 3 × 10 ^ 7

= 3 × 10  ^4 m /s

Centripetal acceleration will be:

ac = v  ²/ r

  = ( 3 × 10  ^4 ) ²/(1.8 × 10  ^11 )

  = 5× 10⁻ ³m /s