The earth, radius 6400 km, makes one revolution about its own axis in 24 hours. The centripetal acceleration of a point on its equator is nearly
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Solution:-
the time period of earth’s rotation is,
T = 24 h = 86400 s
Angular velocity, ω = 2π/T
Radius of earth, r = 6400 km
=> 640000 m
Now, centripetal acceleration = ω^2r
=> (2π/T)2r = 0.034 m/s^2
= 3.4 cm/s^2
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@GauravSaxena01
Answered by
28
Answer:
3.4cm/s^2
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