Question

the earth revolves around the sun with an angular velocity of 2*10-7 rad/s in a circular orbit of radius 1.5*108 km. the force exerted by sun on earth is

Answer 1

PROBLEM    06 – 0675:    The earth (mass = 6 × 1024 kg) revolves around the sun with

                                        angular velocity 2 × 10–7rad/sec in a circular orbit of radius

                                        1.5 × 108 km. The force exerted by the sun on the earth is

                                        = ………… N

                                        (A) 18 × 1025                    (b) zero

                                        (C) 27 × 1039                    (D) 36 × 1021

 

Solution:                 Answer:        (D) 36 × 1021

                    Force exerted by sun of earth = mw2R

                    given = m = 6 × 1024 kg.

                                w = 2 × 10–7 rad/s

                                R = 1.5 × 108 km

                    ∴           F = (6 × 1024)(2 × 10–7)2(1.5 × 108 × 103)

                                    = 36 × 1021 N     

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Answer 2

we know, F=mv^2/r
and w = v/r
therefore Force exerted by sun of earth = mw2R
given = m = 6 × 1024 kg  
w = 2 × 10–7 rad/s
R = 1.5 × 108 km
 ∴   F = (6 × 1024)(2 × 10–7)2 (1.5 × 108 × 103)
force exerted on earth by moon= 36 × 1021 N    Ans..