Question

the eccentricity of the ellipse if the minor axis is equal to the distance between the foci is​

Answer 1

Answer:

b²=a²(1-e²)

is the eccentricity in case of ellipse

Answer 2

$\huge\mathfrak\red{ Answer :-}$

Distance between the foci is 2ae and length of the minor axis =2b. Hence, 2ae = 2b So, ae = b.

But b² = a² (1-e²)

a² e² = a²-a² e²

2a² e² = a² or e² = 1/2. e = 1/√2

Hence, the eccentricity of the eclipse = 1/√2

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