Question

The eccentricity of the ellipse x^2/36 + y^2/16 =1

Answer 1

Answer:

Step-by-step explanation:

Eccentricity of ellipse=$\sqrt{a^2-b^2/a^2}$

=$\sqrt{36-16/36}$

=$\sqrt{20}$/6

=2$\sqrt{5}$/6

=$\sqrt{5}$/3

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