Question

The eccentricity of the ellipse x²/36 + y²/16 =1,
√5/3
3/√5
3/5
5/3​

Answer 1

Answer:

2036.

Step-by-step explanation:

Equation of ellipse : x236+y216=1x236+y216=1

Comparing with x2a2+y2b2=1x2a2+y2b2=1

∴ a2=36andb2=16∴ a2=36andb2=16

⇒ a=6andb=4⇒ a=6andb=4

Here,a>bHere,a>b.

∴∴ Major axis of the ellipse will along x-axis.

Vertices ≡(±a,0)≡(±6,0)≡(±a,0)≡(±6,0)

Eccentricity e=1−b2a2−−−−−−√=1−1636−−−−−−√=2036−−−√e=1-b2a2=1-1636=2036