Question

The eccentricity of the hyperbola 9y² - 4x² = 36

Answer 1

y^2/4-x^2/9=1
so
b=2
a=3
now
a^2=b^2(e^2-1)
4/9+1=e^2
so
e^2=13/9
e=sqrt13/3

Answer 2

9y²-4x²=36sketch the hyperbolas