Question

The edge length of a body centered cubic crystal of an element is 2.8 A. The radius of the constituent atom is​

Answer 1

Answer : The radius of the constituent atom is $1.2\AA$

Explanation :

The relation between edge length and radius of atom in BCC unit cell is:

$a=\frac{4r}{\sqrt{3}}$

where,

a = edge length of unit cell  = $2.8\AA$

r = nearest neighbor distance  or radius of the constituent atom = ?

Now put all the given values in this formula, we get :

$2.8\AA=\frac{4\times r}{\sqrt{3}}$

$r=1.2\AA$

Therefore, the radius of the constituent atom is $1.2\AA$