The edge length of a face centered cubic cell of an ionic substance is 600 pm. if the radius of anion is 190 pm then radius of cation will be
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Answer:
110 pm.
Explanation:
For CCP (or) FCC we have ,
Radius of cation + radius of anion = a/2.
where a = edge length.
let radius of cation is x.
Given radius of anion = 190 pm.
Given edge length (a) = 600 pm.
so, x + 190 = 600/2
== x = 300_190
== x = 110 pm.
Radius of cation (x) = 110 pm.
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