Question

The edge length of a face centered cubic cell of an ionic substance is 600 pm. if the radius of anion is 190 pm then radius of cation will be

Answer 1

Answer:

110 pm.

Explanation:

For CCP (or) FCC we have ,

Radius of cation + radius of anion = a/2.

where a = edge length.

let radius of cation is x.

Given radius of anion = 190 pm.

Given edge length (a) = 600 pm.

so, x + 190 = 600/2

== x = 300_190

== x = 110 pm.

Radius of cation (x) = 110 pm.