Question

the edge length of fcc cell is 508 pm , the radius of anion is?​

Answer 1

Answer:

For an fcc solid, edge length ,

a=2(r++r−)

⇒2(110+r−)=508

⇒220+2r−=508

⇒2r−=508−220

⇒2r−=288

∴r−=144pm

Answer 2

Heyaa mate...

2(r+ + r-)=a

2(rna + rcl )=564pm

rna= 564/2-181=101pm

hope this helped you..✌