The edge length of fcc of an ionic solid is 508pm, if radius of cation is 110pm then radius of anion is?
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For an fcc solid, edge length , a=2(r^+ +r^−)a=2(r^+ +r^−)
⇒2(110+r−)=508⇒2(110+r−)=508
⇒220+2r−=508⇒220+2r−=508
⇒2r−=508−220⇒2r−=508−220
⇒2r−=288⇒2r−=288
∴r−=144pm
⇒2(110+r−)=508⇒2(110+r−)=508
⇒220+2r−=508⇒220+2r−=508
⇒2r−=508−220⇒2r−=508−220
⇒2r−=288⇒2r−=288
∴r−=144pm
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Answer:
r = 144 pm
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