The edge of a cube is decreasing at the rate of 0.6 cm/sec. Find the rate at which its volume is decreasing when the edge of the cube is 2 cm.
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Explanation:
Solution
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Let x be the edge of the cube and V be its volume at any time t.
Then V=x
3
Differentiating w.r.t t we get
dt
dA
=3x
2
dt
dx
Now,
dt
dx
=
sec
0.6 cm
and x=2 cm
∴
dt
dV
=3(2)
2
(0.6)
+7.2
Hence, the volume of the cube is decreasing at the rate of
sec
7.2 cm
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