Question

The edge of a cube is increasing at the rate of 0.3 cm/s, the rate of change of its surface area when edge is 3 cm is __________________.​

Answer 1

Answer:

1 vote

Let the edge =x Then volume V =x³ Hence DV/dt=3x²dx/dt When x= 5 cm and dx/dt=10cm/sec ... More

3 votes

If s is the length of each side of the cube and V is the volume, then ds/dt=10 V=s^3 dV/dt=3×s^2 ... More

0 votes

750cm^3/sec More

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