Question

The edges of a match box are 1.5 cm 3cm and 4cm 10ng. what must be the minimum volume of a packet to contain 24 match boxes?

Answer 1

Answer:

volume= 4320 cm³

Step-by-step explanation:

l=1.5cm

b=3cm

h=4cm

Volume of a box=  1.5*3*4

=1.5*12

=180cm³

Volume of 24 match boxes= 180*24

= 4320 cm³

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