Question

the edges of a triangular board are 3m, 4m and 5m if the cost of painting it is Rs. 10 per m^2 then find the total cost of painting it at only one face. pls answer correctly and spammers will be reported. ​

Answer 1

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1, 0)(1,0)(3,3)\qbezier(5,0)(5,0)(3,3)\qbezier(5,0)(1,0)(1,0)\put(2.85,3.2){ \bf A }\put(0.5,-0.3){ \bf C }\put(5.2,-0.3){ \bf B }\end{picture}$

Let AB = a = 3m; AC = b = 4m and BC = c = 5m.

According to Heron's Formula;

Area = $\sqrt{s (s - a) (s - b) (s - c)}$

where s = semi-perimeter = $\dfrac{a + b + c}{2}$ = $\dfrac{3 + 4 + 5}{2} = \dfrac{12}{2} = 6$

(s - a) = 6 - 3 = 3

(s - b) = 6 - 4 = 2

(s - c) = 6 - 5 = 1

Substituting in Heron's Formula;

Area = $\sqrt{6\times 3 \times 2 \times 1 } = \sqrt{36} =6m^{2}$

Cost for painting 1m² Area of board = ₹10

Cost of painting 6m² Area of board = 6 × 10 = ₹60/-

Answer: Cost of painting the Triangular board on one face = ₹60/-

Additional Information:

For finding the Area of a Traingle when Base and Height is given, we use the Formula: $\dfrac{1}{2} \times Base \times Height$

Answer 2

Answer:

hope above ans is correct..